The first term of an arithmetic progression is 5 and the common difference is 3. What is the sum of the first 10 terms?

✓ Correct Answer: Option B

The nth term is a_n = a + (n-1)d. So, the 10th term is a_10 = 5 + (10-1)3 = 5 + 27 = 32. The sum of the first n terms is S_n = n/2 * (a + a_n). So, S_10 = 10/2 * (5 + 32) = 5 * 37 = 185.