In an arithmetic progression, the 3rd term is 15 and the 7th term is 27. What is the 10th term?

✓ Correct Answer: Option C

Let 'a' be the first term and 'd' be the common difference. a+2d=15 and a+6d=27. Subtracting yields 4d=12, so d=3. Substituting d=3 into a+2d=15 gives a+6=15, so a=9. The 10th term is a+9d = 9+9(3) = 9+27 = 36.