If x^(1/2) = 5 and y^3 = 27, what is the value of (x/y)^2?

✓ Correct Answer: Option D

From x^(1/2) = 5, squaring both sides gives x = 5^2 = 25. From y^3 = 27, taking the cube root gives y = 3. Now, substitute these values into (x/y)^2: (25/3)^2 = 25^2 / 3^2 = 625 / 9.