If (x + y)^2 = 100 and (x - y)^2 = 36, what is the value of xy?

✓ Correct Answer: Option B

Expand the equations: x^2 + 2xy + y^2 = 100 and x^2 - 2xy + y^2 = 36. Subtracting the second from the first yields (x^2 + 2xy + y^2) - (x^2 - 2xy + y^2) = 100 - 36. This simplifies to 4xy = 64. Dividing by 4 gives xy = 16.