If x and y are positive integers such that x < y and x² + y² = 100, what is the value of x?

✓ Correct Answer: Option C

We need to find two positive integers whose squares sum to 100, with x < y. The Pythagorean triple (6, 8, 10) fits: 6² + 8² = 36 + 64 = 100. Since x < y, x must be 6.