If p is a prime number and p^2 is a factor of 720, how many possible values are there for p?

A 1

B 2

C 3

D 4

✓ Correct Answer: Option B

The prime factorization of 720 is 2^4 * 3^2 * 5^1. For p^2 to be a factor, p must be a prime number whose square divides 720. Possible primes are 2 and 3: 2^2=4 (divides 720) and 3^2=9 (divides 720). 5^2=25 does not divide 720. Thus, there are 2 possible values for p (2 and 3).

💡 Why is B) the correct answer?

The correct answer to the question "If p is a prime number and p^2 is a factor of 720, how many possible values are there for p?" is Option B: 2.

The other options — A) 1, C) 3, D) 4 — are incorrect for this GMAT Exam Prep question. As explained above: The prime factorization of 720 is 2^4 * 3^2 * 5^1. For p^2 to be a factor, p must be a prime number whose square divides 720. Possible primes are 2 and 3: 2^2=4 (divides 720) and 3^2=9 (divides 720).…

📚 About This GMAT Exam Prep Practice Question

This 3-level GMAT Exam Prep question from the Quantitative Reasoning topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free GMAT Exam Prep practice test or use flashcards for spaced repetition review.

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If p is a prime number and p^2 is a factor of 720, how many possible values are there for p?

✓ Correct Answer: Option B

📚 About This GMAT Exam Prep Practice Question

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