If p is a prime number and p^2 is a factor of 720, how many possible values are there for p?

✓ Correct Answer: Option B

The prime factorization of 720 is 2^4 * 3^2 * 5^1. For p^2 to be a factor, p must be a prime number whose square divides 720. Possible primes are 2 and 3: 2^2=4 (divides 720) and 3^2=9 (divides 720). 5^2=25 does not divide 720. Thus, there are 2 possible values for p (2 and 3).