If one root of the quadratic equation 2x^2 + bx - 10 = 0 is 5, what is the value of b?

✓ Correct Answer: Option B

Substitute x=5 into the equation: 2(5)^2 + b(5) - 10 = 0. This simplifies to 50 + 5b - 10 = 0, so 40 + 5b = 0. Thus, 5b = -40, and b = -8.