If 8^x = 16^(x-1), what is the value of x?

✓ Correct Answer: Option D

Rewrite both bases with a common base of 2: (2^3)^x = (2^4)^(x-1). This simplifies to 2^(3x) = 2^(4x-4). Equating the exponents: 3x = 4x - 4. Subtracting 3x from both sides gives 0 = x - 4, so x = 4.