An isosceles triangle has sides of length x, x, and y. If the perimeter of the triangle is 32 and y = x + 2, what is the length of the shortest side?

✓ Correct Answer: Option B

The perimeter is x + x + y = 32, so 2x + y = 32. Substituting y = x + 2 yields 2x + (x + 2) = 32, which simplifies to 3x + 2 = 32. Thus, 3x = 30, and x = 10. The sides are 10, 10, and 12, so the shortest side is 10.