A cylindrical tank has a radius of R and a height of H. If its radius is doubled and its height is halved, what is the ratio of the new volume to the original volume?

✓ Correct Answer: Option B

Original volume V_orig = πR²H. New radius = 2R, new height = H/2. New volume V_new = π(2R)²(H/2) = π(4R²)(H/2) = 2πR²H. The ratio V_new / V_orig = (2πR²H) / (πR²H) = 2/1.