A committee of 3 members is to be selected from a group consisting of 5 marketing specialists and 4 finance specialists. How many different unique committees can be formed if there are no restrictions on the specialization of the members?
✓ Correct Answer: Option C
There are 5 + 4 = 9 total specialists. Since the order of selection does not matter for a committee, we use combinations. The number of ways to choose 3 from 9 is C(9, 3) = 9! / (3! * 6!) = (9 * 8 * 7) / (3 * 2 * 1) = 3 * 4 * 7 = 84.
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