A box contains 5 red balls and 3 blue balls. If two balls are drawn at random without replacement, what is the probability that the first ball is red and the second ball is blue?

✓ Correct Answer: Option C

The probability of the first ball being red is 5 (red balls) / 8 (total balls) = 5/8. After one red ball is drawn, there are 7 balls left (4 red, 3 blue). The probability of the second ball being blue is 3 (blue balls) / 7 (remaining balls) = 3/7. The combined probability is (5/8) * (3/7) = 15/56.