What is the standard equation of a circle with center (-2, 3) and radius 4?

A (x + 2)² + (y - 3)² = 4

B (x - 2)² + (y + 3)² = 16

C (x + 2)² + (y - 3)² = 16

D (x - 2)² + (y + 3)² = 4

✓ Correct Answer: Option C

The standard equation is (x-h)² + (y-k)² = r². Given (h,k) = (-2,3) and r = 4, substitute to get (x - (-2))² + (y - 3)² = 4², which simplifies to (x + 2)² + (y - 3)² = 16.

💡 Why is C) the correct answer?

The correct answer to the question "What is the standard equation of a circle with center (-2, 3) and radius 4?" is Option C: (x + 2)² + (y - 3)² = 16.

The other options — A) (x + 2)² + (y - 3)² = 4, B) (x - 2)² + (y + 3)² = 16, D) (x - 2)² + (y + 3)² = 4 — are incorrect for this CLEP Exam Prep question. As explained above: The standard equation is (x-h)² + (y-k)² = r². Given (h,k) = (-2,3) and r = 4, substitute to get (x - (-2))² + (y - 3)² = 4², which simplifies to (x + 2)² + (y - 3)² = 16.

📚 About This CLEP Exam Prep Practice Question

This 2-level CLEP Exam Prep question from the College Algebra topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free CLEP Exam Prep practice test or use flashcards for spaced repetition review.

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What is the standard equation of a circle with center (-2, 3) and radius 4?

✓ Correct Answer: Option C

📚 About This CLEP Exam Prep Practice Question

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