🎓 CLEP Exam Prep

What is the standard equation of a circle with center (-2, 3) and radius 4?

A (x + 2)² + (y - 3)² = 4
B (x - 2)² + (y + 3)² = 16
C (x + 2)² + (y - 3)² = 16
D (x - 2)² + (y + 3)² = 4

✓ Correct Answer: Option C

The standard equation is (x-h)² + (y-k)² = r². Given (h,k) = (-2,3) and r = 4, substitute to get (x - (-2))² + (y - 3)² = 4², which simplifies to (x + 2)² + (y - 3)² = 16.

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