Write the standard form of the equation of a circle with center (-2, 3) and radius 5?

A (x - 2)^2 + (y + 3)^2 = 25

B (x + 2)^2 + (y - 3)^2 = 25

C (x + 2)^2 + (y - 3)^2 = 5

D (x - 2)^2 + (y + 3)^2 = 5

✓ Correct Answer: Option B

The standard form of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius. Substituting h=-2, k=3, and r=5 gives (x - (-2))^2 + (y - 3)^2 = 5^2, which simplifies to (x + 2)^2 + (y - 3)^2 = 25.

💡 Why is B) the correct answer?

The correct answer to the question "Write the standard form of the equation of a circle with center (-2, 3) and radius 5?" is Option B: (x + 2)^2 + (y - 3)^2 = 25.

The other options — A) (x - 2)^2 + (y + 3)^2 = 25, C) (x + 2)^2 + (y - 3)^2 = 5, D) (x - 2)^2 + (y + 3)^2 = 5 — are incorrect for this CLEP Exam Prep question. As explained above: The standard form of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius. Substituting h=-2, k=3, and r=5 gives (x - (-2))^2 + (y - 3)^2 = 5^2, which simplifies to…

📚 About This CLEP Exam Prep Practice Question

This 2-level CLEP Exam Prep question from the College Algebra topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free CLEP Exam Prep practice test or use flashcards for spaced repetition review.

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Write the standard form of the equation of a circle with center (-2, 3) and radius 5?

✓ Correct Answer: Option B

📚 About This CLEP Exam Prep Practice Question

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