What is the radius of the circle given by the equation (x - 2)² + (y + 3)² = 16?

A 2

B 3

C 4

D 16

✓ Correct Answer: Option C

The standard equation of a circle is (x - h)² + (y - k)² = r², where r is the radius. In this equation, r² = 16, so the radius r = √16 = 4.

💡 Why is C) the correct answer?

The correct answer to the question "What is the radius of the circle given by the equation (x - 2)² + (y + 3)² = 16?" is Option C: 4.

The other options — A) 2, B) 3, D) 16 — are incorrect for this CLEP Exam Prep question. As explained above: The standard equation of a circle is (x - h)² + (y - k)² = r², where r is the radius. In this equation, r² = 16, so the radius r = √16 = 4.

📚 About This CLEP Exam Prep Practice Question

This 1-level CLEP Exam Prep question from the College Algebra topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free CLEP Exam Prep practice test or use flashcards for spaced repetition review.

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What is the radius of the circle given by the equation (x - 2)² + (y + 3)² = 16?

✓ Correct Answer: Option C

📚 About This CLEP Exam Prep Practice Question

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