What is the product of the complex numbers (2 + 3i) and (1 - 2i)?
✓ Correct Answer: Option B
Using FOIL: (2)(1) + (2)(-2i) + (3i)(1) + (3i)(-2i) = 2 - 4i + 3i - 6i². Since i² = -1, this simplifies to 2 - i + 6 = 8 - i.
Using FOIL: (2)(1) + (2)(-2i) + (3i)(1) + (3i)(-2i) = 2 - 4i + 3i - 6i². Since i² = -1, this simplifies to 2 - i + 6 = 8 - i.