What is the domain of the function f(x) = sqrt(x² - 9)?

A (-∞, 3] ∪ [3, ∞)

B (-∞, -3] ∪ [3, ∞)

C [-3, 3]

D (0, ∞)

✓ Correct Answer: Option B

For the square root to be defined, the expression inside must be non-negative: x² - 9 ≥ 0. This factors as (x - 3)(x + 3) ≥ 0, which holds true when x ≤ -3 or x ≥ 3.

💡 Why is B) the correct answer?

The correct answer to the question "What is the domain of the function f(x) = sqrt(x² - 9)?" is Option B: (-∞, -3] ∪ [3, ∞).

The other options — A) (-∞, 3] ∪ [3, ∞), C) [-3, 3], D) (0, ∞) — are incorrect for this CLEP Exam Prep question. As explained above: For the square root to be defined, the expression inside must be non-negative: x² - 9 ≥ 0. This factors as (x - 3)(x + 3) ≥ 0, which holds true when x ≤ -3 or x ≥ 3.

📚 About This CLEP Exam Prep Practice Question

This 2-level CLEP Exam Prep question from the College Algebra topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free CLEP Exam Prep practice test or use flashcards for spaced repetition review.

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What is the domain of the function f(x) = sqrt(x² - 9)?

✓ Correct Answer: Option B

📚 About This CLEP Exam Prep Practice Question

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