What is the domain of the function f(x) = sqrt(x² - 9)?
✓ Correct Answer: Option B
For the square root to be defined, the expression inside must be non-negative: x² - 9 ≥ 0. This factors as (x - 3)(x + 3) ≥ 0, which holds true when x ≤ -3 or x ≥ 3.
For the square root to be defined, the expression inside must be non-negative: x² - 9 ≥ 0. This factors as (x - 3)(x + 3) ≥ 0, which holds true when x ≤ -3 or x ≥ 3.