What is the center of the circle described by the equation (x - 5)^2 + (y + 1)^2 = 36?

A (5, 1)

B (-5, 1)

C (5, -1)

D (-5, -1)

✓ Correct Answer: Option C

The standard form of a circle's equation is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center. Comparing with the given equation, h=5 and k=-1.

💡 Why is C) the correct answer?

The correct answer to the question "What is the center of the circle described by the equation (x - 5)^2 + (y + 1)^2 = 36?" is Option C: (5, -1).

The other options — A) (5, 1), B) (-5, 1), D) (-5, -1) — are incorrect for this CLEP Exam Prep question. As explained above: The standard form of a circle's equation is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center. Comparing with the given equation, h=5 and k=-1.

📚 About This CLEP Exam Prep Practice Question

This 1-level CLEP Exam Prep question from the College Algebra topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free CLEP Exam Prep practice test or use flashcards for spaced repetition review.

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What is the center of the circle described by the equation (x - 5)^2 + (y + 1)^2 = 36?

✓ Correct Answer: Option C

📚 About This CLEP Exam Prep Practice Question

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