How many grams of NaCl are needed to prepare 500mL of a 0.9% (w/v) solution?

A 9 g

B 4.5 g

C 0.9 g

D 45 g

✓ Correct Answer: Option B

0.9% w/v = 0.9g per 100mL. For 500mL: 0.9 × 5 = 4.5g.

💡 Why is B) the correct answer?

The correct answer to the question "How many grams of NaCl are needed to prepare 500mL of a 0.9% (w/v) solution?" is Option B: 4.5 g.

The other options — A) 9 g, C) 0.9 g, D) 45 g — are incorrect for this PCAT Exam Prep question. As explained above: 0.9% w/v = 0.9g per 100mL. For 500mL: 0.9 × 5 = 4.5g.

📚 About This PCAT Exam Prep Practice Question

This 2-level PCAT Exam Prep question from the Quantitative Reasoning topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free PCAT Exam Prep practice test or use flashcards for spaced repetition review.

Practice PCAT Exam Prep Quizzes → Browse All Questions Study Flashcards

How many grams of NaCl are needed to prepare 500mL of a 0.9% (w/v) solution?

✓ Correct Answer: Option B

📚 About This PCAT Exam Prep Practice Question

Related PCAT Exam Prep Questions