🎓 CLEP Exam Prep

How many distinct real solutions does the system of equations have: y = x² - 4 and y = 2x - 1?

A 0
B 1
C 2
D 3

✓ Correct Answer: Option C

Set the equations equal: x² - 4 = 2x - 1. Rearranging gives x² - 2x - 3 = 0. Factoring results in (x-3)(x+1) = 0. The distinct solutions are x=3 and x=-1, meaning two distinct real solutions.

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