How many distinct real solutions does the system of equations have: y = x² - 4 and y = 2x - 1?

A 0

B 1

C 2

D 3

✓ Correct Answer: Option C

Set the equations equal: x² - 4 = 2x - 1. Rearranging gives x² - 2x - 3 = 0. Factoring results in (x-3)(x+1) = 0. The distinct solutions are x=3 and x=-1, meaning two distinct real solutions.

💡 Why is C) the correct answer?

The correct answer to the question "How many distinct real solutions does the system of equations have: y = x² - 4 and y = 2x - 1?" is Option C: 2.

The other options — A) 0, B) 1, D) 3 — are incorrect for this CLEP Exam Prep question. As explained above: Set the equations equal: x² - 4 = 2x - 1. Rearranging gives x² - 2x - 3 = 0. Factoring results in (x-3)(x+1) = 0. The distinct solutions are x=3 and x=-1, meaning two distinct real solutions.

📚 About This CLEP Exam Prep Practice Question

This 3-level CLEP Exam Prep question from the College Algebra topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free CLEP Exam Prep practice test or use flashcards for spaced repetition review.

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How many distinct real solutions does the system of equations have: y = x² - 4 and y = 2x - 1?

✓ Correct Answer: Option C

📚 About This CLEP Exam Prep Practice Question

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