Henderson-Hasselbalch equation is:

A pH = pKb + log[B]/[BH+]

B pH = pKa + log([A−]/[HA])

C pH = −log[H+] only

D pH = 14 − pOH only

✓ Correct Answer: Option B

H-H equation: relates pH to pKa and the ratio of conjugate base to acid. Essential for buffer calculations.

💡 Why is B) the correct answer?

The correct answer to the question "Henderson-Hasselbalch equation is:" is Option B: pH = pKa + log([A−]/[HA]).

The other options — A) pH = pKb + log[B]/[BH+], C) pH = −log[H+] only, D) pH = 14 − pOH only — are incorrect for this PCAT Exam Prep question. As explained above: H-H equation: relates pH to pKa and the ratio of conjugate base to acid. Essential for buffer calculations.

📚 About This PCAT Exam Prep Practice Question

This 2-level PCAT Exam Prep question from the Chemical Processes topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free PCAT Exam Prep practice test or use flashcards for spaced repetition review.

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Henderson-Hasselbalch equation is:

✓ Correct Answer: Option B

📚 About This PCAT Exam Prep Practice Question

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