For the quadratic function f(x) = x^2 - 8x + 15, what is the minimum value of the function?
✓ Correct Answer: Option A
The x-coordinate of the vertex is -b/(2a) = -(-8)/(2*1) = 4. The minimum value is f(4) = (4)^2 - 8(4) + 15 = 16 - 32 + 15 = -1.
The x-coordinate of the vertex is -b/(2a) = -(-8)/(2*1) = 4. The minimum value is f(4) = (4)^2 - 8(4) + 15 = 16 - 32 + 15 = -1.