Condense the logarithmic expression: 2log(x) + log(y) - 3log(z)?

✓ Correct Answer: Option B

Using log properties: a log(b) = log(b^a), and log(a) + log(b) - log(c) = log((ab)/c). So, 2log(x) + log(y) - 3log(z) becomes log(x^2) + log(y) - log(z^3), which condenses to log((x^2 y)/z^3).