An sp hybridized carbon forms:

A 4 single bonds

B 2 sigma bonds and 2 pi bonds (as in a triple bond)

C 3 sigma bonds

D No bonds

✓ Correct Answer: Option B

sp hybridization: 2 sp orbitals form σ bonds + 2 unhybridized p orbitals form π bonds (e.g., in alkynes −C≡C−).

💡 Why is B) the correct answer?

The correct answer to the question "An sp hybridized carbon forms:" is Option B: 2 sigma bonds and 2 pi bonds (as in a triple bond).

The other options — A) 4 single bonds, C) 3 sigma bonds, D) No bonds — are incorrect for this PCAT Exam Prep question. As explained above: sp hybridization: 2 sp orbitals form σ bonds + 2 unhybridized p orbitals form π bonds (e.g., in alkynes −C≡C−).

📚 About This PCAT Exam Prep Practice Question

This 2-level PCAT Exam Prep question from the Chemical Processes topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free PCAT Exam Prep practice test or use flashcards for spaced repetition review.

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An sp hybridized carbon forms:

✓ Correct Answer: Option B

📚 About This PCAT Exam Prep Practice Question

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