💊 PCAT Exam Prep

An sp hybridized carbon forms:

A 4 single bonds
B 2 sigma bonds and 2 pi bonds (as in a triple bond)
C 3 sigma bonds
D No bonds

✓ Correct Answer: Option B

sp hybridization: 2 sp orbitals form σ bonds + 2 unhybridized p orbitals form π bonds (e.g., in alkynes −C≡C−).

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