A uniform solid disk with mass M and radius R is free to rotate about its center. A tangential force F is applied at its rim. What is the angular acceleration of the disk? (Moment of inertia I = 1/2 MR^2 for a solid disk)
✓ Correct Answer: Option B
Torque τ = FR. Using τ = Iα and I = (1/2)MR^2, we get FR = (1/2)MR^2 α. Solving for α gives α = 2F / (MR).