A parallel-plate capacitor has a capacitance C₀. If the area of the plates is doubled and the distance between them is halved, what is the new capacitance?

✓ Correct Answer: Option D

Capacitance C is proportional to plate area A and inversely proportional to plate separation d (C = ε₀A/d). Doubling A and halving d results in C' = ε₀(2A)/(d/2) = 4(ε₀A/d) = 4C₀.