A mass-spring system oscillates with a period T on a frictionless surface. If the mass attached to the spring is doubled, what is the new period of oscillation?

✓ Correct Answer: Option C

The period of a mass-spring system is T = 2π√(m/k). If the mass (m) is doubled to 2m, the new period T' = 2π√(2m/k) = √2 * (2π√(m/k)) = √2 T.