A mass m is attached to a spring with spring constant k, oscillating on a frictionless horizontal surface. If the mass is quadrupled, how does the period of oscillation change?
✓ Correct Answer: Option C
The period of a mass-spring system is T = 2π√(m/k). If mass (m) is quadrupled, T' = 2π√(4m/k) = 2 * 2π√(m/k) = 2T. The period doubles.