A 2 kg block slides down a frictionless ramp from a height of 3 meters. What is its speed at the bottom of the ramp, assuming it starts from rest? (Use g = 10 m/s²)
✓ Correct Answer: Option C
By conservation of mechanical energy, potential energy (mgh) converts to kinetic energy (0.5mv²). Thus, v = √(2gh) = √(2 * 10 m/s² * 3 m) = √60 m/s.