What is the distance between the points (-2, 5) and (4, -3) in the xy-plane?
✓ Correct Answer: Option C
Use the distance formula: d = √[(x₂ - x₁)² + (y₂ - y₁)²]. d = √[(4 - (-2))² + (-3 - 5)²] = √[(6)² + (-8)²] = √[36 + 64] = √100 = 10.
Use the distance formula: d = √[(x₂ - x₁)² + (y₂ - y₁)²]. d = √[(4 - (-2))² + (-3 - 5)²] = √[(6)² + (-8)²] = √[36 + 64] = √100 = 10.