Two capacitors of 6 μF and 3 μF in series have a total capacitance of:

✓ Correct Answer: Option B

Series: 1/C = 1/C₁ + 1/C₂ = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2. C = 2 μF.