The Taylor series expansion of sin(x) about x=0 starts with: A 1 − x²/2 B x − x³/6 + x⁵/120 C x + x³/6 D 1 + x ✓ Correct Answer: Option B sin(x) = x − x³/3! + x⁵/5! − ... = x − x³/6 + x⁵/120 − ... Practice FE Exam Prep Quizzes → Browse All Questions Study Flashcards