The resonant frequency of a series RLC circuit is: A f = 1/(RC) B f = 1/(2π√(LC)) C f = RL D f = LC ✓ Correct Answer: Option B At resonance, X_L = X_C: ω₀ = 1/√(LC), so f₀ = 1/(2π√(LC)). Practice FE Exam Prep Quizzes → Browse All Questions Study Flashcards