The pH of a 0.01 M HCl solution is:
✓ Correct Answer: Option B
HCl is a strong acid that fully dissociates. [H+] = 0.01 M = 10^-2 M, so pH = -log(10^-2) = 2.
HCl is a strong acid that fully dissociates. [H+] = 0.01 M = 10^-2 M, so pH = -log(10^-2) = 2.