Solve the inequality: -3x + 10 ≤ 1?
✓ Correct Answer: Option A
Subtract 10 from both sides: -3x ≤ -9. Then, divide by -3 and remember to reverse the inequality sign because you are dividing by a negative number: x ≥ 3.
Subtract 10 from both sides: -3x ≤ -9. Then, divide by -3 and remember to reverse the inequality sign because you are dividing by a negative number: x ≥ 3.