In a parallel plate capacitor, doubling the distance between plates while keeping charge constant will:

A Double the capacitance

B Halve the capacitance

C Double the voltage

D Both B and C

✓ Correct Answer: Option D

C = εA/d: doubling d halves C. Since Q = CV and Q is constant, V must double.

💡 Why is D) the correct answer?

The correct answer to the question "In a parallel plate capacitor, doubling the distance between plates while keeping charge constant will:" is Option D: Both B and C.

The other options — A) Double the capacitance, B) Halve the capacitance, C) Double the voltage — are incorrect for this MCAT Exam Prep question. As explained above: C = εA/d: doubling d halves C. Since Q = CV and Q is constant, V must double.

📚 About This MCAT Exam Prep Practice Question

This 3-level MCAT Exam Prep question from the Chemical & Physical Foundations topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free MCAT Exam Prep practice test or use flashcards for spaced repetition review.

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In a parallel plate capacitor, doubling the distance between plates while keeping charge constant will:

✓ Correct Answer: Option D

📚 About This MCAT Exam Prep Practice Question

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