If 3^x * 9^y = 2187, and 2^(x+y) = 16, what is the value of x?

✓ Correct Answer: Option B

Rewrite the equations with common bases: 3^x * (3^2)^y = 3^7 => x + 2y = 7. And 2^(x+y) = 2^4 => x + y = 4. Subtracting (x+y=4) from (x+2y=7) yields y = 3. Substitute y=3 into x+y=4 to get x+3=4, so x=1.