If 2^(x+3) = 16^y, and 3^(2y-1) = 27, what is the value of x?

✓ Correct Answer: Option B

From 3^(2y-1) = 27 = 3^3, we get 2y-1 = 3, so 2y = 4, and y = 2. Substitute y=2 into the first equation: 2^(x+3) = 16^2 = (2^4)^2 = 2^8. Thus, x+3 = 8, which means x = 5.