How many distinct 3-letter codes can be formed using the letters A, B, C, D, E if no letter can be repeated and the code must start with a vowel?

✓ Correct Answer: Option B

The available letters are A, B, C, D, E. Vowels are A, E (2 choices). The first letter must be a vowel, so there are 2 options. For the second letter, 4 options remain. For the third, 3 options remain. Total codes = 2 * 4 * 3 = 24.