⚙️ FE Exam Prep

For the ODE y'' + 4y = 0, the general solution is:

A y = Ae^(2x) + Be^(−2x)
B y = A cos(2x) + B sin(2x)
C y = (A+Bx)e^(2x)
D y = Ax² + Bx

✓ Correct Answer: Option B

Characteristic equation: r² + 4 = 0, r = ±2i. Complex roots → y = A cos(2x) + B sin(2x).

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