⚙️ FE Exam Prep

An inductor in DC steady state acts as:

A An open circuit
B A short circuit (wire)
C A capacitor
D A voltage source

✓ Correct Answer: Option B

In DC steady state, di/dt = 0, so V_L = L(di/dt) = 0. The inductor acts as a short circuit (wire).

💡 Why is B) the correct answer?

The correct answer to the question "An inductor in DC steady state acts as:" is Option B: A short circuit (wire).

The other options — A) An open circuit, C) A capacitor, D) A voltage source — are incorrect for this FE Exam Prep question. As explained above: In DC steady state, di/dt = 0, so V_L = L(di/dt) = 0. The inductor acts as a short circuit (wire).

📚 About This FE Exam Prep Practice Question

This 2-level FE Exam Prep question from the Circuits topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free FE Exam Prep practice test or use flashcards for spaced repetition review.

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