A list of 7 integers is arranged in ascending order. The median is 18 and the range is 15. If the smallest integer is 10, what is the largest possible value of the third integer in the list?

✓ Correct Answer: Option C

Let the list be a1, a2, a3, a4, a5, a6, a7. Given a1=10, a4=18 (median), and a7-a1=15. So a7=25. The list is 10, a2, a3, 18, a5, a6, 25. To maximize a3, it must be less than or equal to the median (18). Since integers are arranged in ascending order, a3 can be at most 18.