A cylindrical tank has a radius r and height h. If both the radius and height are doubled, what is the ratio of the new volume to the original volume?

✓ Correct Answer: Option C

The original volume V = πr^2h. When the radius is doubled (2r) and height is doubled (2h), the new volume V' = π(2r)^2(2h) = π(4r^2)(2h) = 8πr^2h. Thus, the new volume is 8 times the original volume, so the ratio is 8:1.