A bag contains 5 red balls and 3 blue balls. If two balls are drawn at random without replacement, what is the probability that both balls are red?

A 5/14

B 1/4

C 9/28

D 25/64

✓ Correct Answer: Option A

The probability of drawing the first red ball is 5/8. After one red ball is drawn, there are 4 red balls left out of 7 total. The probability of drawing a second red ball is 4/7. The combined probability is (5/8) * (4/7) = 20/56 = 5/14.

💡 Why is A) the correct answer?

The correct answer to the question "A bag contains 5 red balls and 3 blue balls. If two balls are drawn at random without replacement, what is the probability that both balls are red?" is Option A: 5/14.

The other options — B) 1/4, C) 9/28, D) 25/64 — are incorrect for this GRE Exam Prep question. As explained above: The probability of drawing the first red ball is 5/8. After one red ball is drawn, there are 4 red balls left out of 7 total. The probability of drawing a second red ball is 4/7. The combined probabi…

📚 About This GRE Exam Prep Practice Question

This 3-level GRE Exam Prep question from the Quantitative Reasoning topic is part of BrainForge Quiz's free exam preparation library. Each question includes the correct answer and a detailed explanation to help you understand the underlying concept, not just memorize the answer.

How to use this page: Read the question above, consider all four options (A through D), then check the highlighted correct answer and explanation. For active timed practice, start a free GRE Exam Prep practice test or use flashcards for spaced repetition review.

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A bag contains 5 red balls and 3 blue balls. If two balls are drawn at random without replacement, what is the probability that both balls are red?

✓ Correct Answer: Option A

📚 About This GRE Exam Prep Practice Question

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