A 10 ohm resistor carries 2 A of current. The power dissipated is:
✓ Correct Answer: Option B
P = I²R = (2)²×10 = 40 W. Alternatively, V = IR = 20 V, then P = IV = 2×20 = 40 W.
P = I²R = (2)²×10 = 40 W. Alternatively, V = IR = 20 V, then P = IV = 2×20 = 40 W.